/**
 *  fileName:反转字符串
 *  time:2021/9/17
 *  todo:编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

  

 示例 1：

 输入：["h","e","l","l","o"]
 输出：["o","l","l","e","h"]
 示例 2：

 输入：["H","a","n","n","a","h"]
 输出：["h","a","n","n","a","H"]

 作者：力扣 (LeetCode)
 链接：https://leetcode-cn.com/leetbook/read/top-interview-questions-easy/xnhbqj/
 https://leetcode-cn.com/problems/reverse-string/solution/fan-zhuan-zi-fu-chuan-by-leetcode-solution/
 来源：力扣（LeetCode）
 著作权归作者所有。商业转载请联系作者获得授权，非商业转载请注明出处。
 */
/**
 * @param {character[]} s
 * @return {void} Do not return anything, modify s in-place instead.
 */
// var reverseString = function(s) {
//   let a
//   let len = s.length
//   let len2 = Math.floor(len / 2)
//   for (let i = 0; i < len2; i++) {
//     a = s[i]
//     s[i] = s[len - i - 1]
//     s[len - i - 1] = a
//   }
// };
var reverseString = function (s) {
  let len = s.length
  for (let left = 0, right = len - 1; left < right; left++, right--) {
    [s[left], s[right]] = [s[right], s[left]]
  }
}
